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Ammonia

40 ml of ammo...

Question

$40 m l$ of ammonia gas, taken in an audiometer tube, was subjected to sparks till the volume did not further change. The volume was found to increase by $40 m l . 40 m l$ of oxygen gas then mixed and the mixture was further exploded. The gases remained were $30 m l$ . Deduce the formula of ammonia. (Ammonia contain $N$ and $H$ only).

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Solution

Let formula of Ammonia be $N x H y$
$N x H y \to \frac{x}{2} N_{2} + \frac{y}{2} H_{2}$
$\frac{x}{2} \times 40 m l + \frac{y}{2} \times 40 m l = 40 + 40 m l$
$20 (x + y) = 80$
$x + y = 4$ .....(i)
$1 m o l H_{2}$ required $\frac{1}{2} m o l O_{2}$
$\frac{y}{2} m o l H_{2}$ required $\frac{y}{4} m o l O_{2}$
Amount of $O_{2}$ left $= 40 - 40 \times \frac{Y}{4}$
$= 40 - 10 Y$
$40 - 104 + \frac{x}{2} \times 40 = 30$
$40 + 20 x - 10 y = 30$
$20 x - 10 y = - 10$
$2 x - y = - 1$ ....(ii)
Solve equation (i) and (ii)
we get $x = 1 y = 3$
Formula of Ammonia = $N H_{3}$

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