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Experimental/Empirical Probability

Question 19 4...

Question

Question 19

40% of [100 - 20% of 300] is equal to
(a) 20
(b) 16
(c) 140
(d) 64

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Solution

40% of [100 - 20% of 300]
$= \frac{40}{100} \times [100 - \frac{20}{100} \times 300] = \frac{40}{100} [100 - 60] = \frac{40}{100} \times 40 = 4 \times 4 = 16$

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Question 19

40% of [100 - 20% of 300] is equal to
(a) 20
(b) 16
(c) 140
(d) 64

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Question 40

In $Δ A B C$ , $∠ A = 100^{\circ}$ , AD bisects $∠ A$ and $A D ⊥ B C$ . Then, $∠ B$ is equal to

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Question 19

In the given figure, BC = CA and $∠ A = 40^{\circ}$ . Then, $∠ A C D$ is equal to

a) $40^{\circ}$
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Q. Question 4
In the figure, if

∠ A B C = 20^{\circ}

∠ A O C

(A) 20º
(B) 40º
(C) 60º
(D) 10º

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