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Byju's Answer
Standard XII
Physics
Introducing Epsilon
40.The averag...
Question
40.The average value of sawtooth voltage V=V^°{2t/T-1} over 0 to T/2 is given by
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Similar questions
Q.
The voltage over a cycle varies as
V
=
V
0
s
i
n
ω
t
f
o
r
0
≤
t
≤
π
ω
and
V
=
−
V
0
s
i
n
ω
t
f
o
r
π
ω
≤
t
≤
2
π
ω
Then the average value of voltage is
Q.
The voltage supplied to a circuit is given by
V
=
V
0
t
3
/
2
, where
t
is time in second. Find the
r
m
s
value of voltage for the period,
t
=
0
to
t
=
1
s
.
Q.
For a given A.C voltage
V
=
V
0
sin
ω
t
, if
V
1
is average voltage of half cycle and
V
2
is rms voltage, then
V
1
V
2
is
Q.
The rms value for the saw-tooth voltage of peak value
V
0
from
t
=
0
to
t
=
2
T
as shown in the figure is
V
0
√
x
. Find the value of
x
.
Q.
For any arbitrary motion in space, which of the following relations are true : (a) v _average = (1/2) (v (t₁) + v (t₂)) (b) v _average = [r(t₂) - r(t₁) ] /(t₂ – t₁) (c) v (t) = v (0) + a t (d) r (t) = r (0) + v (0) t + (1/2) a t₂ (e) a _average =[ v (t2) - v (t₁ )] /( t₂ – t₁) (The ‘average’ stands for average of the quantity over the time interval t₁to t2)
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