$400 c m^{3}$ of oxygen at $27^{\circ} C$ were cooled to $- 3^{\circ} C$ without change in pressure. The contraction in volume will be

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Solution

The correct option is A

$V_{2} = \frac{T_{2}}{T_{1}} . V_{1} = \frac{270^{\circ} K}{300^{\circ} K} . 400 c m^{3} = 360 c m^{3}$
$c o n t r a c t i o n = V_{1} - V_{2} = 400 - 360 = 40 c m^{3}$

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