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Byju's Answer

Standard VI

Physics

Thermal Equilibrium

400 g of ice ...

Question

400 g of ice at 253 K is mixed with 0.05 kg of steam at $100^{o} C$ . Latent heat of vaporisation of steam $= 540 c a l g^{- 1}$ . Latent heat of fusion of ice $= 80 c a l g^{- 1}$ . Specific heat of ice $= 0.5 c a l g^{- 1}^{o} C^{- 1}$ . Find the resultant temperature of the mixture.

253 K

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260 K

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273 K

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290 K

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Solution

The correct option is C 273 K
Heat lost by 0.05 kg of steam at $100^{o} C$ to water at $0^{o} C$
$Q_{L} = (50 \times 540) + (50 \times 1 \times 100)$
$= 27000 + 5000 = 32000 c a l$
Heat required by 400 g of ice at 253 K $(- 20^{o} C)$ to convert into water at 273 K $10^{o} C) Q_{1} = (400 \times 0.5 \times 20) + (400 \times 80)$
$= (4000 + 32000) = 36000 c a l$
$∴ Q_{L} < Q_{1}$ , only part of ice melts and final temperature remains $0^{o} C$ or 273 K.

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Similar questions

400 g

of ice at 253 K is mixed with

0.05 k g

of steam at

100^{\circ} C

. Latent heat of vaporisation of steam is equal to 540 cal

g^{- 1}

. Latent heat of fusion of ice is equal to 80 cal

g^{- 1}

, Specific heat of ice is equal to 0.5 cal

g^{- 1}

^{\circ} C^{- 1}

. Find the resultant temperature of the mixture.

Q. Calculate the mass of steam at

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needed to just melt 320 g of ice at

- 10^{\circ} C

. The specific heat of ice

= 0.5 c a l g^{- 1}^{\circ} C^{- 1}

, latent heat of vaporization of steam

= 540 c a l g^{- 1},

specific heat of fusion of ice

= 80 c a l g^{- 1}

Q. 5 g of water at

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and 5 g of ice at

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are mixed together in a calorimeter. What is the final temperature of the mixture. Given specific heat of ice

= 0.5 c a l g^{- 1} (^{o} C)^{- 1}

and latent heat of fusion of ice

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10 g

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in a calorimeter. The final temperature of the mixture is [Specific heat of water

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60 g

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400 g of ice at 253 K is mixed with 0.05 kg of steam at 100oC. Latent heat of vaporisation of steam =540calg−1. Latent heat of fusion of ice =80calg−1. Specific heat of ice =0.5calg−1oC−1. Find the resultant temperature of the mixture.

400 g of ice at 253 K is mixed with 0.05 kg of steam at $100^{o} C$ . Latent heat of vaporisation of steam $= 540 c a l g^{- 1}$ . Latent heat of fusion of ice $= 80 c a l g^{- 1}$ . Specific heat of ice $= 0.5 c a l g^{- 1}^{o} C^{- 1}$ . Find the resultant temperature of the mixture.