400 g of vegetable oil of specific heat capacity 1-98 J g -1 - C -1 is cooled from 100 -C- Find the final temperature- if the heat energy given out by is 47376 J-

Liquid A of specific heat capacity 1 J g⁻¹ K⁻¹ at a temperature of $50^{\circ} C$ is mixed with 100g of a liquid B of specific heat capacity 2 J g⁻¹ K⁻¹ at $30^{\circ} C$ .The final temperature of mixture becomes $40^{\circ} C$ . Find the mass of liquid A.

75 g

of water at

10^{o} C

is heated by supplying

25200 J

of heat energy. If the specific heat capacity of water is

4.2 J / g^{o} C

. Calculate the final temperature of water

Calculate the amount of ice which is required to cool 150 g of water contained in a vessel of mass 100 g at 30°C, such that the final temperature of the mixture is 5^oC. Take specific heat capacity of material of vessel as 0.4 J g^-1 ^oC^-1 ; specific latent heat of fusion of ice = 336 J g^-1 ; specific heat capacity of water = 4.2 J g^-1 °C^-1.

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400 g of vegetable oil of specific heat capacity 1.98 J g−1 ∘C−1) is cooled from 100∘C. Find the final temperature, if the heat energy given out by is 47376 J.

The correct option is A 40.2∘CGiven , m=400g,θ1=1000C,θ2=? , specific heat of vegetable oil c=1.98J/g−oC,Q=47376JNow , by the definition of specific heat c , Q=mcΔθ=mc(θ1−θ2)or 47376=400×1.98(100−θ2)or (100−θ2)=47376/(400×1.98)=59.8or θ2=100−59.8=40.2oC

400 g of vegetable oil of specific heat capacity 1.98 J $g^{- 1}$ $^{\circ} C^{- 1}$ ) is cooled from $100^{\circ} C$ . Find the final temperature, if the heat energy given out by is 47376 J.