₹4000 increased to ₹5000 in 8 years for a certain rate of interest. In
Let the rate of interest be R.
Given,
Time period, (n)=8 years
We know that,
Interest, I=PTR100
5000−4000=4000×8×R100 R=1000×1004000×8 R=258%
In the second case, it is given
I=₹2400−₹1600=₹800
Let the time period be n for rate of interest, 258%.
Then, interest is given by
800=1600×25×n100×8 n=800×8×1001600×25 n=16 years
∴ It will take 16 years for ₹1600 to amount to ₹2400 at the same rate.