Question

$42000J$ of heat energy is supplied to $175g$ of iron at ${30}^{o}C$, when the final temperature recorded is ${430}^o$. Calculate specific heat capacity of iron

• A. $600J{g}^{-1}$ ${}^o{C}^{-1}$
• B. $0.6J{g}^{-1}$ ${}^o{C}^{-1}$
• C. $60J{g}^{-1}$ ${}^o{C}^{-1}$
• D. $6J{g}^{-1}$ ${}^o{C}^{-1}$

Answer 1

Answer: (B)

$0.6J{g}^{-1}$ ${}^o{C}^{-1}$

Change in temperature $=430-30={400}^{o}C$

let the specific heat be $cJ/g$ ${}^{o}C$

Heat supplied $Q=mc\Delta T$

So, $42000=175\times c\times 400$

$c=0.6J/g$ ${}^{o}C$