The correct option is C 25 439 = (4× 9) + 3 , the relation is (first digit × last digit) + middle digit. ...

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Standard XII

Mathematics

Definition of Sets

439 : 39 : : ...

Question

$439 : 39 :: 298 : ?$

73

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25

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68

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29

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Solution

The correct option is C $25$
$439 = (4 \times 9) + 3$ , the relation is (first digit $\times$ last digit) $+$ middle digit.

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439:39::298:?

The correct option is C 25439=(4×9)+3, the relation is (first digit × last digit) + middle digit.

$439 : 39 :: 298 : ?$

The correct option is C $25$
$439 = (4 \times 9) + 3$ , the relation is (first digit $\times$ last digit) $+$ middle digit.