Question

4398.48 can be written in expanded form as: $4\times {10}^a+b\times {10}^2+9\times {10}^c+8\times {10}^0+4\times {10}^d+e\times {10}^{-2}$. Find the value of a + b + c -d -e?

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

The correct option is A

0

4398.48 can be written as $4\times {10}^3+3\times {10}^2+9\times {10}^1+8\times {10}^0+4\times {10}^{-1}+8\times {10}^{-2}$
Hence, a= 3
b = 3
c = 1
d = -1
e = 8
The value of a + b + c -d -e = 3 + 3 + 1 - (-1) -8 = 0.