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Question

44.8 L of CO2 at NTP is obtained by heating x g of pure CaCO3.x is:

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Solution

CaCO3CaO+CO2
no. of moles of CO2 in 44.8L at NTP.
No. of moles=Volume of gasVolume at NTP
n=44.8L22.4L=2 moles of CO2.
As 1 mole of CO2 is produced by 1 mole of CaCO3 thus,
2 moles of CO2 is produced by 2 moles of CaCO3.
Amount of CaCO3 present in 2 mole of CaCO3,
m=2 mole×100gmol1
n=200g

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