Question

$44$ cows can graze a field in $9$ days. How many less/more cows will graze the same field in $12$ days?

Answer 1

Given, $44$ cows can graze a field in $9$ days.

It means,

In $9$ days, the number of cows that can graze the field $=44$ cows.

In $1$ day, the number of cows that can graze the same field $=44\times 9$ cows.

In $12$ days, the number of cows required to graze the field $=\frac{44\times 9}{12}=\frac{44\times 3}{4}=11\times 3=33$ cows.

Hence, $33$ cows are required to graze the same field in $12$ days.

Alternate way

$\begin{array}{ccc}\text{Number of Cows}& 44& x\\ \text{Days}& 9& 12\end{array}$

More cows less days or less cows more days to graze the feil.

So, it is a case of inverse proportion.

$\therefore 44\times 9=x\times 12$

$\Rightarrow x=\frac{44\times 9}{12}$

$\Rightarrow x=33$