44.The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is

Open in App

Solution

Suggest Corrections

Similar questions

The wavelength of the first line of lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is:

Q. The wavelength of the first line of Lyman series for hydrogen is identical to that of the second line of Balmer series for some hydrogen-like ion

X

. Calculate energies of the first four levels of

X

. Also, find its ionization potential. (Given: Ground state binding energy of the hydrogen atom is

13.6 e V

)

Q. If the series limit of Lyman series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then the atomic number of this hydrogen like atom is -

Q. The shortest wavelength of the Lyman series of hydrogen is equal to the shortest wavelength of the Balmer series of a hydrogen-like atom of atomic number

^{'} Z^{'}

. The value of

Z

Q. What hydrogen-like ion has the wavelength difference between the first lines of Balmer and Lyman series equal to

59.3 n m

(R_{H} = 109678 {c m}^{- 1})

Join BYJU'S Learning Program