Question

$45g$ of acid of molecular weight 90 is neutralized by $200ml$ of 5N caustic potash. What is the basicity of the acid?

Answer 1

We know,
Meq. of Acid = Meq. of caustic potash

$\therefore \frac{45}{\frac{90}{n}}\times 1000=200\times 5\Rightarrow \frac{n}{2}\times 1000=200\times 5$
$\Rightarrow n=2$