450 mL of a strong acid solution of pH = 2.0 is mixed with 550 mL of another acid solution of pH = 3.0. The pH of resultant solution is
2.31
[H+] from 450 ml pH 2.0 solution = 0.01x(450)/1000
[H+] from 550 ml pH 3.0 solution = 0.001x(550)/1000
Adding both [H+] = 5.05 x 10-3
Hence, pH≈2.3
(log 5 = 0.7)