$(47 - 7 \frac{1}{2}) + \frac{1}{2}$ equals

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
40

We know that $(x - y) + z = x - (y - z)$ , for all numbers $x$ , $y$ , $z$ with $y > z$ .

Since the above is true for all the numbers, it must be true for $x = 47$ , $y = 7 \frac{1}{2}$ and $z = \frac{1}{2}$ also, as $y = 7 \frac{1}{2} > \frac{1}{2} = z$

So, $(47 - 7 \frac{1}{2}) + \frac{1}{2}$ = $47 - (7 \frac{1}{2} - \frac{1}{2})$ = $47 - (\frac{15}{2} - \frac{1}{2})$ = $47 - 7$ = $40$

Suggest Corrections

Similar questions

(47 - 7 \frac{1}{2}) + \frac{1}{2}

75 \times 35 \times 47 \times 63 \times 71 \times 87 \times 82

(3, - 2)

\frac{3}{4}

2 x - y + 3 = 0

The value of $72^{2} - 71^{2}$ is equal to

Join BYJU'S Learning Program