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Byju's Answer
Standard XII
Physics
Motion Under Variable Acceleration
47.The positi...
Question
47.The position of a body moving along x axis given by x= (2t3 + 3t2 + 5). The acceleration of particle at the instant its velocity becomes zero is
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Q.
The position of a particle moving along x-axis given by
x
=
(
−
2
t
3
+
3
t
2
+
5
)
m
. The acceleration of particle at the instant its velocity becomes zero is
Q.
A particle moves along x-axis and its displacement at any time is given by
x
(
t
)
=
2
t
3
−
3
t
2
+
4
t
in SI units. The velocity of the particle when its acceleration is zero, is:
Q.
A particle starts moving along the x-axis from
t
=
0
, its position varying with time as
x
=
2
t
3
−
3
t
2
+
1
,
a. At what time instants is its velocity zero?
b. What is the velocity when it passes through the origin?
Q.
A particle moves along a straight line such that its position
x
at any time
t
is given given by.
x
=
2
t
3
−
12
t
2
+
6
t
+
8
The velocity of the particle when its acceleration is zero is (
x
is in metre and
t
is in second)
Q.
The acceleration of a particle which moves along the positive x-axis varies with its position as shown. The velocity of the particle is
0.8
m
/
s
at
x
=
0
and the acceleration becomes zero after
x
=
1.4
m
. The maximum velocity of the particle (in m/s) is
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