48. 2 (sin 45 raise to the power 4-cos cube 60)+(tan square 30cot square 45) is equal to ?

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4 {sin}^{2} 60 + 3 {tan}^{2} 30 - 8 sin 45. cos 45

x^{2} {tan}^{2} 60^{o} - 4 x {cos}^{2} 45^{o} = 4 sin 30^{o} cos 60^{o} tan 45^{o}

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\frac{5 {sin}^{2} 30^{0} + {cos}^{2} 45^{0} + 4 {tan}^{2} 60^{0}}{2 sin 30^{0} cos 60^{0} + tan 45^{0}}

4 (s i n^{4} 30^{0} + c o s^{4} 60^{0}) (c o s^{2} 45^{0} - s i n^{2} 90^{0}) + t a n^{4} 45^{0} - c o t^{2} 45^{0}

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