48.67 % (w/W) HCl stock solution has a density of 1.5gmL−1. The molecular weight of HCl is 36.5gmol−1.The volume (mL) of stock required to prepare 200 mL of 0.4 M HCl is: ___
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Solution
Mass of HCl in 1.0 mL stock solution = 1.5×48.67100=0.73005g Mass of HCl required for 200 mL 0.4 M HCl = 2001000×0.4×36.5=0.08×36.5g ∴ 0.7301 g of HCl is present in 1.0 mL stock solution. 0.08×36.5gHCl will be present in 0.08×36.50.7301≈4.00mL