CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sulphuric Acid

48. A sample ...

Question

48. A sample of sulphuric acid is 49% by mass . 100 ml of it on titration with 12 N NaOH required 50ml of NaOH solution . The density of the sample of sulphuric acid is

Open in App

Solution

Suggest Corrections

thumbs-up

4

Similar questions

0.6234

g sample that might contain

N a O H, N a_{2} C O_{3}, N a H C O_{3}

or a mixture of

N a O H + N a_{2} C O_{3}

N a_{2} C O_{3} + N a H C O_{3}

is titrated with

0.1062 M H C l

by two-indicator method. It is found that

40.38

mL of the acid is required to reach the phenolphthalein end-point. Methyl orange is then added to the solution and the titration continued using an additional

12.83

mL of the acid. Thus, the sample contained :

1.6

g of pyrolusite ore was treated with

50

0.1 N

oxalic acid and some sulphuric acid. The oxalic acid left in excess was raised to

250

25

mL of this solution when titrated with

0.01 N

K M n O_{4}

30

mL of the solution. The percentage of pure

M n O_{2}

in the sample is :

0.1 N K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} .4 H_{2} O

solution reacts completely with

20 ml of 0.05 M

K M n O_{4}

solution in acidic medium. Another sample of the same solution of

K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} .4 H_{2} O

having the same volume is titrated with

\frac{1}{8} M N a O H

solution. Then, the volume of

N a O H

solution (in ml) required for titration is:

Q. 1 g of fuming sulphuric acid

(H_{2} S O_{4} + S O_{3})

, called oleum, is diluted with water. This solution is completely neutralised 26.7 ml of 0.4 M NaOH. Find the percentage of free

S O_{3}

in the sample solution.

Q. 100 mL of sulphuric acid solution (sp. gr. =1.84) contains 98% by weight of pure acid. Calculate the volume of 0.46 M NaOH solution (in L) required to just neutralize the above acid solution.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Oxoacids of Sulphur

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon