The correct option is A 2401Here, (7^2)^3 ÷ (7)^2 = ? ⇒ (7)^6 ÷ 7^2 = ? ⇒ 7^6 2 = ? [∵ 7^6 ÷ 7^2 = 7^6 2] ⇒ ? = 7^4 = 7 × 7 × 7 × 7 = 2401 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Base Systems

493÷72=?

Question

$(49)^{3} \div (7)^{2} = ?$

2401

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

343

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2401
$H e r e, (7^{2})^{3} \div (7)^{2} = ? \Rightarrow (7)^{6} \div 7^{2} = ? \Rightarrow 7^{6 - 2} = ? [∵ 7^{6} \div 7^{2} = 7^{6 - 2}] \Rightarrow ? = 7^{4} = 7 \times 7 \times 7 \times 7 = 2401$

Suggest Corrections

Similar questions

(7^{2} s^{- 2}) \times (49^{3 / 2} \div s^{3})^{- 2}

s

49^{- 5} \times 49^{3}

\sqrt[3]{7} \times \sqrt[3]{49} .

\begin{matrix} \begin{matrix} - & 2 & 0 & 6 \end{matrix} \\ \begin{matrix} + & 9 & 8 \end{matrix} \\ \begin{matrix}  \end{matrix} \end{matrix}

\begin{matrix} \begin{matrix} + & 1 & 7 & 8 \end{matrix} \\ \begin{matrix} - & 6 & 9 \end{matrix} \\ \begin{matrix}  \end{matrix} \end{matrix}

\begin{matrix} \begin{matrix} - & 1 & 0 & 3 \end{matrix} \\ \begin{matrix} + & 3 & 1 & 2 \end{matrix} \\ \begin{matrix}  \end{matrix} \end{matrix}

\begin{matrix} \begin{matrix} - & 4 & 9 & 3 \end{matrix} \\ \begin{matrix} + & 2 & 8 & 9 \end{matrix} \\ \begin{matrix}  \end{matrix} \end{matrix}

Join BYJU'S Learning Program