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Byju's Answer
Standard XII
Chemistry
Molarity
49 gm of H2...
Question
49 gm of
H
2
S
O
4
react with 1 L of water. Find the molarity of the solution
A
M
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B
2 M
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C
3 M
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D
0.5 M
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Solution
The correct option is
D
0.5 M
Molarity=
W
e
i
g
h
t
o
f
s
o
l
u
t
e
i
n
g
r
a
m
M
o
l
e
c
u
l
a
r
w
e
i
g
h
t
x
V
o
l
u
m
e
(
i
n
l
i
t
r
e
)
49
98
×
1
=
0.05
M
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0
Similar questions
Q.
Commercially available
H
2
S
O
4
is
98
gms by weight of
H
2
S
O
4
and
2
gms by weight of water. It's density is
1.83
g
c
m
−
3
. Calculate the molality (m) of
H
2
S
O
4
solution.
[Take : Molar mass of
H
2
S
O
4
as
98
g
m
o
l
−
1
].
Q.
Sulphuric acid reacts with sodium hydroxide as follows
H
2
S
O
4
+
2
N
a
O
H
→
N
a
2
S
O
4
+
2
H
2
O
When 1 L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained is ?
Q.
Calculate the pH of the mixture : 8 g of NaOH +680 mL of 1 M HCl+10 mL of
H
2
S
O
4
, (specific gravity 1.2, 49%
H
2
S
O
4
by mass). The total volume of the solution was made to 1 L with water:
Q.
100
m
L
o
f
H
2
S
O
4
solution having molarity
1
M
and density
1.5
g
/
m
L
is mixed with
400
m
L
water. Calculate final molarity of
H
2
S
O
4
solution, if final density is
1.25
g
/
m
L
:
Q.
The normality of a solution that results from mixing
4
g of NaOH,
500
mL of
1
M HCl, and
10.0
mL of
H
2
S
O
4
(specific gravity =
1.1
,
49
%
H
2
S
O
4
by weight) is :
(The total volume of solution was made to
1
L with water)
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