4b4 is divisible by 4 when b is:
3
5
6
7
For a number to be divisible by 4, the last two digits have to form a number that is a multiple of 4.
Therefore the value of b must be 0,2,4,6 or 8.
As 6 is the only relevant option, the answer is 6.
Solve for x: 3x−5=13
When 5pq(p2−q2) is divided by 2p(p+q) and substituting p=3,q=1, the value obtained is:
What is the remainder when 4x3 - 7x + 6 is divided by x – 1?
If (4, 19) is a solution of the equation y=ax+3, then a =