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Question

4Fe(s)+3O2(g)2Fe2O3(s)
For the following reaction, ΔS=549.4 J K1 mol1 at 298 K. ΔrH=1648×103 J mol1
The reaction is spontaneous

A
True
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B
False
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Solution

The correct option is A True
One decides the spontaneity of a reaction by considering ΔSTotal(ΔSsys+ΔSsurr). For calculating ΔSsurr, we have to consider the heat absorbed by the surroundings which is equal to ΔrH. At temperature T, entropy change of the surrounding is
ΔSsurr=ΔrHT (at constant pressure)
=(1648×103 J mol1)298 K
=5530 J K1 mol1
Thus, total entropy change for this reaction
ΔrStotal=5530 J K1 mol1+(549.4 J K1 mol1)
=4980.6 J K1 mol1
This shows that the above reaction is spontaneous.

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