4L of 0.02M aqueous solution of NaCl was diluted by adding 1L of water. The molality of the sol. Is

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Solution

Molarity of NaCl = 0.02 M
No. of moles of NaCl =0.02 x 4 = 0.08 moles

Final Volume of solution = 4 +1 =5 litres
Mass of 5 L water = 5 kg

Molality = No. of moles of solute / kg of solvent = 0.08 moles / 5 kg = 0.016 m

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4L of 0.02M aqueous solution of NaCl was diluted by adding 1L of water. The molality of the sol. Is

Molarity of NaCl = 0.02 M No. of moles of NaCl =0.02 x 4 = 0.08 moles Final Volume of solution = 4 +1 =5 litres Mass of 5 L water = 5 kg Molality = No. of moles of solute / kg of solvent = 0.08 moles / 5 kg = 0.016 m

Molarity of NaCl = 0.02 M
No. of moles of NaCl =0.02 x 4 = 0.08 moles

Final Volume of solution = 4 +1 =5 litres
Mass of 5 L water = 5 kg

Molality = No. of moles of solute / kg of solvent = 0.08 moles / 5 kg = 0.016 m