(4pq+3q)2 − (4pq−3q)2= ____________.
44pq2
48p2q
48pq2
44p2q
(4pq+3q)2−(4pq−3q)2 We have: (a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2 So, (4pq+3q)2−(4pq−3q)2 =[(4pq)2+(3q)2+2(4pq)(3q)]−[(4pq)2+(3q)2−2(4pq)(3q)] =24pq2+24pq2 =48pq2
Prove that: (4pq+3q)2−(4pq−3q)2=48pq2.
Show that:
(4pq+3q)2−(4pq−3q)2=48pq2