4tan^-1(1/5)-tan^-1(1/239) is equal to

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4 t a n^{- 1} \frac{1}{5} - t a n^{- 1} \frac{1}{239}

4 {tan}^{- 1} \frac{1}{5} - {tan}^{- 1} \frac{1}{239}

Find the value of 4 $t a n^{- 1} \frac{1}{5} - t a n^{- 1} \frac{1}{239} .$

x = 4 {tan}^{- 1} (\frac{1}{5}), y = {tan}^{- 1} (\frac{1}{70})

z = {tan}^{- 1} (\frac{1}{99})

x

x = 4 {tan}^{- 1} (\frac{1}{5}), y = {tan}^{- 1} (\frac{1}{70})

z = {tan}^{- 1} (\frac{1}{99})

x - y + z

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