The correct option is C 16x^2 1 Given that: (4x+1)×(4x 1) We can see that: #160; #160; (4x+1)×(4x 1)= #160; #160; 4x×(4x 1)+1× (4x ...

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Multiplication of Any Polynomial

4x + 14x - 1 ...

Question

$(4 x + 1) (4 x - 1) =$

16 x^{2} + 8 x + 2

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16 x^{2} + 8 x + 1

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16 x^{2} - 1

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16 x^{2} + 1

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Solution

The correct option is C $16 x^{2} - 1$
Given that: $(4 x + 1) \times (4 x - 1)$
We can see that: $(4 x + 1) \times (4 x - 1) =$ $4 x \times (4 x - 1) + 1 \times (4 x - 1)$
$\Rightarrow (4 x \times 4 x) - (4 x \times 1) + (1 \times 4 x) - (1 \times 1)$
$\Rightarrow 16 x^{2} - 4 x + 4 x - 1$
$\Rightarrow 16 x^{2} - 1$

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