Question

$4x^3{y}^4$ when divided by $-2y^{2}x$ gives:

• A. $2x^2{y}^2$
• B. $-2x^2{y}^2$
• C. $-2x^3{y}^2$

Answer 1

The correct option is B $-2x^2{y}^2$

$\frac{4x^3{y}^4}{-2y^{2}x}=-\frac{4\times x^3\times y^4}{2\times x\times y^2}$
Canceling the common term in numerator and denominator and subtracting the exponent of respective unknown variables we get,
$\frac{4x^3{y}^4}{-2y^{2}x}=-\frac{4\times x^3\times y^4}{2\times x\times y^2}$
$=-2\times x^{(3-1)}\times y^{(4-2)}$
$=-2x^2{y}^2$