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Question

(4×103)+(2×102)+(0×101)+(2×100)+(1×101)+(2×102) is the expanded form of the number ___.

A
4202.12
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B
4220.12
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C
4202.02
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D
4202.21
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Solution

The correct option is A 4202.12
(4×103)+(2×102)+(0×101)+(2×100)+(1×101)+(2×102)
=4000+200+0+(2×1)+(1×110)+(2×1100) (a0=1)
=4000+200+0+2+0.1+0.02
=4202.12

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