(4×103+3×1+1×10−1+6×100)=
4×103+3×1+1×10−1+6×100=(4×1000)+(3×1)+110+(6×1)=4000+3+0.1+6=4009.1
(4×103+3×1+1×10−1+6×100)=_
Evaluate: (4×103+3×1+1×10−1+6×100)=___
Find the value of
(2×104)+(3×103)+(1×102)+(6×101)+(7×100)+(4×10−1)+(2×10−2)+(8×10−3)