4 - 103-3 - 1-1 - 10-1-6 - 100-

The correct option is D 4009.1 4×10^3+ 3×1 + 1×10^ 1+ 6×10^0 = (4×1000) + (3×1) + 1/10 + (6×1) = 4000 + 3 + 0.1 + 6 = 4009.1 ...

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Byju's Answer

Standard VII

Mathematics

Exponents

4 × 103+3 × 1...

Question

$(4 \times 10^{3} + 3 \times 1 + 1 \times 10^{- 1} + 6 \times 10^{0}) =$ _

4009.1

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4008

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4007.1

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Solution

The correct option is A
4009.1

$4 \times 10^{3} + 3 \times 1 + 1 \times 10^{- 1} + 6 \times 10^{0} = (4 \times 1000) + (3 \times 1) + \frac{1}{10} + (6 \times 1) = 4000 + 3 + 0.1 + 6 = 4009.1$

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Similar questions

$(4 \times 10^{3} + 3 \times 1 + 1 \times 10^{- 1} + 6 \times 10^{0}) =$

___

Evaluate: $(4 \times 10^{3} + 3 \times 1 + 1 \times 10^{- 1} + 6 \times 10^{0}) =$ ___

Find the value of

$(2 \times 10^{4}) + (3 \times 10^{3}) + (1 \times 10^{2}) + (6 \times 10^{1}) + (7 \times 10^{0}) + (4 \times 10^{- 1}) + (2 \times 10^{- 2}) + (8 \times 10^{- 3})$

(1 \times 10^{3}) + (2 \times 10^{2}) + (3 \times 10^{1}) + (4 \times 10^{0}) + (2 \times 10^{- 1}) + (3 \times 10^{- 2})

(1 \times 10^{3}) + (2 \times 10^{2}) + (3 \times 10^{0}) + (1 \times 10^{- 1}) + (2 \times 10^{- 2})

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(4×103+3×1+1×10−1+6×100)=_

The correct option is A 4009.1 4×103+3×1+1×10−1+6×100=(4×1000)+(3×1)+110+(6×1)=4000+3+0.1+6=4009.1

$(4 \times 10^{3} + 3 \times 1 + 1 \times 10^{- 1} + 6 \times 10^{0}) =$ _

The correct option is A
4009.1

$4 \times 10^{3} + 3 \times 1 + 1 \times 10^{- 1} + 6 \times 10^{0} = (4 \times 1000) + (3 \times 1) + \frac{1}{10} + (6 \times 1) = 4000 + 3 + 0.1 + 6 = 4009.1$