4y2+3y+12 by 2y+1
Quotient =2y+12
Remainder = 0
Add: 3+2y−5y2+6y3, −8+3y+7y3 and 5−6y−8y3+y2
Adding 3+2y−5y2+6y3,−8+3y+7y3 and 5−6y−8y3+y2, we get
If 2x2−3xy+y2+x+2y−8=0 then dydx=