Question

$4yz(z^2+6z-16)÷2y(z+8)=\text{\_\_}$

• A. z-2
• B. z(z-2)
• C. 2z(z-2)
• D. None of these

Answer 1

The correct option is C

2z(z-2)

$4yz(z^2+6z-16)$

$=4yz[z^2-2z+8z-16]$

$=4yz\left[z\right(z-2)+8(z-2\left)\right]$

$=4yz(z-2)(z+8)$

$\therefore 4yz(z^2+6z-16)÷2y(z+8)$

$=\frac{4yz(z-2)(z+8)}{2y(z+8)}$

$=2z(z-2)$