Question

4z² + 5 = $\sqrt{3}$ z

Answer 1

Given: 4z² + 5 = $\sqrt{3}$ z
On subtracting $\sqrt{3}$ z from both sides, we get:
4z² + 5 – $\sqrt{3}$ z = $\sqrt{3}$ z – $\sqrt{3}$ z
=> 4z² – $\sqrt{3}$z + 5 = 0
Thus, the standardised form of the given quadratic equation is 4z² – $\sqrt{3}$z + 5 = 0.
On comparing this equation with az² + bz + c = 0 in variable z , we get:
a = 4, b = –$\sqrt{3}$ and c = 5