$_{5}^{10} B$ and $_{5}^{11} B$ are two isotopes of Boron. What is the average atomic mass of B atom if they are present in 45.5 and 54.5 percentages respectively?

11.22

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10.54

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12.36

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Solution

The correct option is B 10.54
Average atomic mass of B $= \frac{10 \times 45.5}{100} + \frac{11 \times 54.5}{100}$
$= 4.55 + 5.99 = 10.54$ .

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105B and 115B are two isotopes of Boron. What is the average atomic mass of B atom if they are present in 45.5 and 54.5 percentages respectively?

The correct option is B 10.54Average atomic mass of B =10×45.5100+11×54.5100 =4.55+5.99=10.54.

$_{5}^{10} B$ and $_{5}^{11} B$ are two isotopes of Boron. What is the average atomic mass of B atom if they are present in 45.5 and 54.5 percentages respectively?

The correct option is B 10.54
Average atomic mass of B $= \frac{10 \times 45.5}{100} + \frac{11 \times 54.5}{100}$
$= 4.55 + 5.99 = 10.54$ .