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Question

# 517+518+519+520 is divisible by

A
7
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B
9
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C
11
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D
13
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Solution

## The correct option is D 7we can also write =>5(18+19+20)=>5(74)=119018554687500check condition for 9We see that,this number is even ending to zero and since the sum of its digit is divisible by 3 (1+1+9+0+1+8+5+5+4+6+8+7+5+0+0)=60 which is divisible by 31190185546875003=39672851562500now, we see that 3+9+6+7+2+8+5+1+5+6+2+5+0+0=59 which is not divisible by 3hence,original number is nit divisible by 9check condition for 111−1+9−0+1−8+5−5+4−6+8−7+5−0+0=6which is not divisible by 11check condition for 7you must ake last digit and double it and subtract this number from the rest of remaining digitnumber is 119018554687500last digit is 0and subtract from remaning digit 11901855468750−0=11901855468750which is not divisible by 7check condition for 13pair of three digit from the right side of digit and arrange with alternating sign of positive negativei.e.,500−687+554−018+119=468=46813=36therfore,the number is divisible by 13

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