$5 (2 x - 7) - 3 (2 x + 3) \leq 0, 2 x + 19 \leq 6 x + 47$

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Solution

$5 (2 x - 7) - 3 (2 x + 3) \leq 0, 2 x + 19 \leq 6 x + 47$
$10 x - 35 - 6 x - 9 \leq 0$
$4 x - 44 \leq 0$
$4 x \leq 44$
$x \leq 11$
and
$2 x + 19 \leq 6 x + 43$
$2 x - 6 x \leq 47 - 19$
$- 4 x \leq 28$
$x \geq 7$
Intersecting of both values
$x ϵ [7, 11]$

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