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Introduction to Alcohols

5.500ml of a ...

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5.500ml of a hydrocarbon on burning in excess of O2 gave 3000ml of CO2 and 3 l of water vapour .what is formula of hydrocarbon

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500 m L

of a gaseous hydrocarbon when burnt in excess of

O_{2}

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of water vapour under same conditions. The molecular formula of the hydrocarbon is :

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500 m L

of a hydrocarbon gas , burnt in excess og oxygen , yields

2500 m L C O_{2}

and 3 liters of water vapour, all volumes being mesured at the same temperature and pressure, what is the formula of the hydrocarbon?

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