Question

5.6 g of a metal forms 12.7 g of metal chloride. Hence, equivalent weight of the metal is :

• A. 127
• B. 254
• C. 56
• D. 28

Answer 1

The correct option is D 28

5.6 g of a metal forms 12.7 g of metal chloride
The amount of chlorine present in 12.7 g of metal chloride is $12.7g-5.6g=7.1g$.
Thus, 5.6 g of metal combines with 7.1 g of chlorine.
The equivalent weight of metal is the weight of metal that combines with 35.5 g of chlorine.
The equivalent weight of metal is $\frac{5.6g\times 35.5g}{7.1g}=28g/eq$.