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Volume of Gases and Number of Moles

5.6 L of oxyg...

Question

5.6 L of oxygen at NTP is equivalent to :

A

1 mole

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B

\frac{1}{2} m o l e

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C

\frac{1}{4} m o l e

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D

1 / 8 m o l e

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Solution

The correct option is A $\frac{1}{4} m o l e$
The correct option is C
5.6 L of $O_{2}$ is equal to
$\frac{56}{22.4}$ =0.25 which is equal to $\frac{1}{4}$ mole

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