5.6 litres of a gas at NTP is found to have a mass of 11 g.
The molecular mass of the gas is:

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Solution

1 mole of a gas at NTP has a volume of 22.4 litres. We use this to get to the answer. It is given that:
$5.6 L - 11 g$
Then, $22.4 L - \frac{(11 \times 22.4)}{5.6} = 44 g$

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