Question

$(5+6\times 3-4)+(5\times 6)\times (14-7)$ $=$ _____.

• A. 34
• B. 83
• C. 256
• D. 229

Answer 1

The correct option is D 229

The order of operation of BODMAS is as follows:

Brackets

Of

Division

Multiplication

Addition

Subtraction

$(5+6\times 3-4)+(5\times 6)\times (14-7)$
$=\left(19\right)+\left(30\right)\times \left(7\right)$
$=19+210$
$=229$

$\therefore (5+6\times 3-4)+(5\times 6)\times (14-7)$ $=229$