$5$ boys & $4$ girls sit in a straight line. Find the number of ways in which they can sit if $2$ girls are together the other $2$ are also together but separate from the first two.

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Solution

There are 7! ways to arrange 5 boys and these two
$∴ 7! - 2 \times 6! = 3600$
Now sticking to these pair, but varying the order
$4 \times 3600 = 14, 000$
Now changing the pair
$3 \times 14, 400 = 43, 200.$

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5 boys & 4 girls sit in a straight line. Find the number of ways in which they can sit if 2 girls are together the other 2 are also together but separate from the first two.

There are 7! ways to arrange 5 boys and these two ∴7!−2×6!=3600Now sticking to these pair, but varying the order 4×3600=14,000Now changing the pair3×14,400=43,200.

$5$ boys & $4$ girls sit in a straight line. Find the number of ways in which they can sit if $2$ girls are together the other $2$ are also together but separate from the first two.

There are 7! ways to arrange 5 boys and these two
$∴ 7! - 2 \times 6! = 3600$
Now sticking to these pair, but varying the order
$4 \times 3600 = 14, 000$
Now changing the pair
$3 \times 14, 400 = 43, 200.$