Question

$5$ boys and $5$ girls had to sit alternately around a round table. This can be done in $N$ ways. Then the value of $N$ is

Answer 1

Five boys can be arranged in a circle in $4!$ ways.
After that, girls can be arranged in the five gaps shown as $‘X^{\prime }$ in $5!$ ways.

Hence, total number of ways $=4!\times 5!=2880$