Question

	$5$ cent coins	$10$ cent coins	$25$ cent coins	Total coins
Offer $1$	$20$	$15$	$4$	$39$
Offer $2$	$25$	$5$	$8$	$38$
Total	$45$	$20$	$12$	$77$

Samira has given two offers on winning a lottery. The offers are tabulated with the number of coins in the above table. Which offer is she most likely to choose?

• A. The coins are worth the same so Samira is equally likely to pick either of them
• B. Offer $1$ is worth more than Offer $2$, so Samira will pick Offer $1$
• C. Offer $2$ is worth more than Offer $1$, so Samira will pick Offer $2$
• D. Samira will reject both the offers

Answer 1

The correct option is C Offer $2$ is worth more than Offer $1$, so Samira will pick Offer $2$

Offer 1

Value of $5$ cent coin $=$ $20\times 5=100$

Value of $10$ cent coin $=$ $15\times 10=150$

Value of $25$ cent coin $=$ $25\times 4=100$

Total value of offer $1=$ $100+150+100=350$

Offer 2

Value of $5$ cent coin $=$ $25\times 5=125$

Value of $10$ cent coin $=$ $10\times 5=50$

Value of $25$ cent coin $=$ $25\times 8=200$

Total value of offer $2=$ $125+50+200=375$

Offer $2>$ offer $1$

Then offer $2$ is worth more than offer $1$, so Samira will pick offer $2$.