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Subtraction of Like Fractions

5 1/4+6 2/3+7...

Question

$5 \frac{1}{4} + 6 \frac{2}{3} + 7 \frac{1}{6} = ?$

19.5

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19 \frac{11}{12}

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19 \frac{1}{12}

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19

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N o n e o f t h e s e

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Solution

The correct option is C $19 \frac{1}{12}$
To add this, we separate the integral part and fractional part.
$S o, (5 + 6 + 7) + (\frac{1}{4} + \frac{2}{3} + \frac{1}{6}) = (18) + (\frac{3 + 4 \times 2 + 2}{12}) = 18 + \frac{13}{12} = 18 + 1 \frac{1}{12} = 19 \frac{1}{12}$

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Multiply the following fractions:

(i) (ii) (iii)

(iv) (v) (vi)

(vii)

1 + (\frac{1}{2} + \frac{1}{3}) \frac{1}{4} + (\frac{1}{4} + \frac{1}{5}) \frac{1}{4^{2}} + (\frac{1}{6} + \frac{1}{7}) \frac{1}{4^{3}} + . . . \infty = {log}_{e} \sqrt{b}

\frac{b}{4}

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