Question

$[5\frac{1}{4}-\frac{2}{5}\times 5\frac{5}{9}+(\frac{1}{2}+\frac{3}{4})]$ is equal to:

• A. $\frac{12}{24}$
• B. $\frac{24}{12}$
• C. $\frac{16}{9}$
• D. $\frac{9}{16}$

Answer 1

The correct option is C

$\frac{16}{9}$

$[5\frac{1}{4}-\frac{2}{5}\times 5\frac{5}{9}+(\frac{1}{2}+\frac{3}{4})]$

= [$\frac{21}{4}$ - {($\frac{2}{5}\times \frac{50}{9}$) + $\frac{5}{4}$}]

= [$\frac{21}{4}$ - {$\frac{20}{9}$ + $\frac{5}{4}$}]

= [$\frac{21}{4}$ - $\frac{125}{36}$]

Taking LCM of denominators, we have

$\frac{189-125}{36}$ = $\frac{64}{36}$ = $\frac{32}{18}$ = $\frac{16}{9}$