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Question

5 g of ice at 00 C and 20 g of water at 450 C are mixed. The temperature of the mixture will be

A
100 C
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B
200 C
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C
300 C
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D
400 C
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Solution

The correct option is B 200 C
Let the final temperature be T
5×80+5×1(T0)=20×1×(45T)400+5T=90020T25T=900400T=50025=20

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