Question

5 g of Zinc is treated separately with an excess of
I. dilute hydrochloric acid and
II. aqueous sodium hydroxide.
The ratio of the volumes of $H_2$ evolved in these two reactions is:

• A. $2:1$
• B. $1:2$
• C. $1:1$
• D. $1:4$

Answer 1

The correct option is C $1:1$

$Zn+2NaOH\to N{a}_{2}Zn{O}_2+H_2$
$Zn+2HCl\to ZnC{l}_2+H_2$
So, the ratio of volume of $H_2$ released in both the cases is $1:1$.